Vị Thanh - commune in Vi Thuy district, Hau Giang province, Vietnam. Article "Vị Thanh (xã)" in Vietnamese Wikipedia has 27.1 points for quality (as of November 1, 2023). The article contains 6 references and 5 sections.
Since the creation of article "Vị Thanh (xã)", its content was written by 12 registered users of Vietnamese Wikipedia and edited by 12 registered Wikipedia users in all languages.
The article is cited 17 times in Vietnamese Wikipedia and cited 17 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Vietnamese: #39803 10.2017 |
Global: #3886980 10.2017 |
| Best Rank | Vietnamese: #3178 03.2023 |
Global: #935200 05.2018 |
On 19 June 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: UEFA Euro 2024, UEFA European Championship, Xherdan Shaqiri, Jamal Musiala, Cristiano Ronaldo, Albania, UEFA Euro 2020, İlkay Gündoğan, Inside Out 2, Juneteenth.
In Vietnamese Wikipedia the most popular articles on that day were: Đài Truyền hình Kỹ thuật số VTC, Đinh Tiến Dũng, Albania, Bảng xếp hạng bóng đá nam FIFA, Giải vô địch bóng đá châu Âu 2024, Giải vô địch bóng đá châu Âu, Gruzia, Thích Minh Tuệ, Đội tuyển bóng đá quốc gia Albania, Thích Chân Quang.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(4.03+3.59+16.67+25+86)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
